Post by Pincho Paxton on Nov 2, 2015 21:59:25 GMT
Link...
Into how many pieces does a balloon burst?
Pincho says...
Hmm, I would rather have a go at it myself...
The first break is star-like so that gives the balloon some starting threads, and the break would be along the areas of least resistance, which means that those areas are the least bonded areas of a plain surface. For the areas to be the weakest, I would say that these areas are diagonal to bonding, so the initial star shape is diagonal to bonding pathways. The thing about the bonded pathways is that it is gravity that bonds along lanes of the balloon like liquid pathways through necklace beads. The liquid pathways generate a flow force against the diagonal break force. So...
1/ Breaking is happening diagonally in a star shape.
2/ Gravity is flowing against the break as a cross-wind type flow.
3/ The break, and the cross-wind combine to fragment the area of least resistance.
4/ Diagonal + crosswind = multiple break displacements.
Something like that.
Pincho Paxton
Into how many pieces does a balloon burst?
...when a crack propagating across the surface of a balloon reaches a critical speed, it becomes unstable and splits into two new cracks.
Pincho says...
Hmm, I would rather have a go at it myself...
The first break is star-like so that gives the balloon some starting threads, and the break would be along the areas of least resistance, which means that those areas are the least bonded areas of a plain surface. For the areas to be the weakest, I would say that these areas are diagonal to bonding, so the initial star shape is diagonal to bonding pathways. The thing about the bonded pathways is that it is gravity that bonds along lanes of the balloon like liquid pathways through necklace beads. The liquid pathways generate a flow force against the diagonal break force. So...
1/ Breaking is happening diagonally in a star shape.
2/ Gravity is flowing against the break as a cross-wind type flow.
3/ The break, and the cross-wind combine to fragment the area of least resistance.
4/ Diagonal + crosswind = multiple break displacements.
Something like that.
Pincho Paxton